2x^2+x+12=4

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Solution for 2x^2+x+12=4 equation:


Simplifying
2x2 + x + 12 = 4

Reorder the terms:
12 + x + 2x2 = 4

Solving
12 + x + 2x2 = 4

Solving for variable 'x'.

Reorder the terms:
12 + -4 + x + 2x2 = 4 + -4

Combine like terms: 12 + -4 = 8
8 + x + 2x2 = 4 + -4

Combine like terms: 4 + -4 = 0
8 + x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4 + 0.5x + x2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + 0.5x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + 0.5x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 0.5x + x2 = 0 + -4
0.5x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
0.5x + x2 = -4

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
0.5x + 0.25 + x2 = -4 + 0.25

Reorder the terms:
0.25 + 0.5x + x2 = -4 + 0.25

Combine like terms: -4 + 0.25 = -3.75
0.25 + 0.5x + x2 = -3.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -3.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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